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\sqrt{2}-2\sqrt{2}+\sqrt{3}-2-\left(\sqrt{2}\right)^{2}
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
-\sqrt{2}+\sqrt{3}-2-\left(\sqrt{2}\right)^{2}
Combine \sqrt{2} and -2\sqrt{2} to get -\sqrt{2}.
-\sqrt{2}+\sqrt{3}-2-2
The square of \sqrt{2} is 2.
-\sqrt{2}+\sqrt{3}-4
Subtract 2 from -2 to get -4.