Solve for x
x=9
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\left(\sqrt{18-2x}\right)^{2}=0
Multiply \sqrt{18-2x} and \sqrt{18-2x} to get \left(\sqrt{18-2x}\right)^{2}.
18-2x=0
Calculate \sqrt{18-2x} to the power of 2 and get 18-2x.
-2x=-18
Subtract 18 from both sides. Anything subtracted from zero gives its negation.
x=\frac{-18}{-2}
Divide both sides by -2.
x=9
Divide -18 by -2 to get 9.
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