Solve sqrt{128}+sqrt{243}

$$\sqrt{ 128 } + \sqrt{ 243 }$$

Evaluate

$$8\sqrt{2}+9\sqrt{3}\approx 26.902165767$$

Solution Steps

Factor 128=8^{2}\times 2. Rewrite the square root of the product \sqrt{8^{2}\times 2} as the product of square roots \sqrt{8^{2}}\sqrt{2}. Take the square root of 8^{2}.

$$8\sqrt{2}+\sqrt{243}$$

Factor 243=9^{2}\times 3. Rewrite the square root of the product \sqrt{9^{2}\times 3} as the product of square roots \sqrt{9^{2}}\sqrt{3}. Take the square root of 9^{2}.

$$8\sqrt{2}+9\sqrt{3}$$