Solve sqrt{12}+sqrt{24}

$$\sqrt{ 12 } + \sqrt{ 24 }$$

Evaluate

$$2\left(\sqrt{3}+\sqrt{6}\right)\approx 8.363081101$$

Solution Steps

Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.

$$2\sqrt{3}+\sqrt{24}$$

Factor 24=2^{2}\times 6. Rewrite the square root of the product \sqrt{2^{2}\times 6} as the product of square roots \sqrt{2^{2}}\sqrt{6}. Take the square root of 2^{2}.

$$2\sqrt{3}+2\sqrt{6}$$