Solve sqrt{12}+sqrt{18}+sqrt{27}-sqrt{32}

$$\sqrt{ 12 } + \sqrt{ 18 } + \sqrt{ 27 } - \sqrt{ 32 }$$

Evaluate

$$5\sqrt{3}-\sqrt{2}\approx 7.246040475$$

Solution Steps

Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.

$$2\sqrt{3}+\sqrt{18}+\sqrt{27}-\sqrt{32}$$

Factor 18=3^{2}\times 2. Rewrite the square root of the product \sqrt{3^{2}\times 2} as the product of square roots \sqrt{3^{2}}\sqrt{2}. Take the square root of 3^{2}.

$$2\sqrt{3}+3\sqrt{2}+\sqrt{27}-\sqrt{32}$$

Factor 27=3^{2}\times 3. Rewrite the square root of the product \sqrt{3^{2}\times 3} as the product of square roots \sqrt{3^{2}}\sqrt{3}. Take the square root of 3^{2}.

$$2\sqrt{3}+3\sqrt{2}+3\sqrt{3}-\sqrt{32}$$

Combine 2\sqrt{3} and 3\sqrt{3} to get 5\sqrt{3}.

$$5\sqrt{3}+3\sqrt{2}-\sqrt{32}$$

Factor 32=4^{2}\times 2. Rewrite the square root of the product \sqrt{4^{2}\times 2} as the product of square roots \sqrt{4^{2}}\sqrt{2}. Take the square root of 4^{2}.

$$5\sqrt{3}+3\sqrt{2}-4\sqrt{2}$$

Combine 3\sqrt{2} and -4\sqrt{2} to get -\sqrt{2}.

$$5\sqrt{3}-\sqrt{2}$$