Solve sqrt{100}-5^3div25-4*6-3^2

$$\sqrt{ 100 } - { 5 }^{ 3 } \div 25-4 \times 6- { 3 }^{ 2 }$$

Evaluate

$$-28$$

Solution Steps

Calculate the square root of 100 and get 10.

$$10-\frac{5^{3}}{25}-4\times 6-3^{2}$$

Calculate 5 to the power of 3 and get 125.

$$10-\frac{125}{25}-4\times 6-3^{2}$$

Divide 125 by 25 to get 5.

$$10-5-4\times 6-3^{2}$$

Subtract 5 from 10 to get 5.

$$5-4\times 6-3^{2}$$

Multiply 4 and 6 to get 24.

$$5-24-3^{2}$$

Subtract 24 from 5 to get -19.

$$-19-3^{2}$$

Calculate 3 to the power of 2 and get 9.

$$-19-9$$

Subtract 9 from -19 to get -28.

$$-28$$

Factor

$$-28$$