Solve sqrt{1-0.64}-sqrt[3]{8}sqrt{4/25}-3+sqrt{7}

$$\sqrt{ 1-0.64 } - \sqrt[3]{ 8 } \sqrt{ \frac{ 4 }{ 25 } } -3+ \sqrt{ 7 }$$

Evaluate

$$\sqrt{7}-3.2\approx -0.554248689$$

Solution Steps

Subtract 0.64 from 1 to get 0.36.

$$\sqrt{0.36}-\sqrt[3]{8}\sqrt{\frac{4}{25}}-3+\sqrt{7}$$

Calculate the square root of 0.36 and get 0.6.

$$0.6-\sqrt[3]{8}\sqrt{\frac{4}{25}}-3+\sqrt{7}$$

Calculate \sqrt[3]{8} and get 2.

$$0.6-2\sqrt{\frac{4}{25}}-3+\sqrt{7}$$

Rewrite the square root of the division \frac{4}{25} as the division of square roots \frac{\sqrt{4}}{\sqrt{25}}. Take the square root of both numerator and denominator.

$$0.6-2\times \frac{2}{5}-3+\sqrt{7}$$

Multiply 2 and \frac{2}{5} to get \frac{4}{5}.

$$0.6-\frac{4}{5}-3+\sqrt{7}$$

Subtract \frac{4}{5} from 0.6 to get -\frac{1}{5}.

$$-\frac{1}{5}-3+\sqrt{7}$$

Subtract 3 from -\frac{1}{5} to get -\frac{16}{5}.

$$-\frac{16}{5}+\sqrt{7}$$