Solve sqrt{0.09}-sqrt{0.36}+sqrt{-6^2}*sqrt{0.2^2}

$$\sqrt{ 0.09 } - \sqrt{ 0.36 } + \sqrt{ { -6 }^{ 2 } } \times \sqrt{ { 0.2 }^{ 2 } }$$

Evaluate

$$0.9$$

Solution Steps

Calculate the square root of 0.09 and get 0.3.

$$0.3-\sqrt{0.36}+\sqrt{\left(-6\right)^{2}}\sqrt{0.2^{2}}$$

Calculate the square root of 0.36 and get 0.6.

$$0.3-0.6+\sqrt{\left(-6\right)^{2}}\sqrt{0.2^{2}}$$

Subtract 0.6 from 0.3 to get -0.3.

$$-0.3+\sqrt{\left(-6\right)^{2}}\sqrt{0.2^{2}}$$

Calculate -6 to the power of 2 and get 36.

$$-0.3+\sqrt{36}\sqrt{0.2^{2}}$$

Calculate the square root of 36 and get 6.

$$-0.3+6\sqrt{0.2^{2}}$$

Calculate 0.2 to the power of 2 and get 0.04.

$$-0.3+6\sqrt{0.04}$$

Calculate the square root of 0.04 and get 0.2.

$$-0.3+6\times 0.2$$

Multiply 6 and 0.2 to get 1.2.

$$-0.3+1.2$$

Add -0.3 and 1.2 to get 0.9.

$$0.9$$

Factor

$$\frac{3 ^ {2}}{2 \cdot 5} = 0.9$$