Solve sqrt{(-2sqrt{3^2})+2^2}

$$\sqrt{ (-2 \sqrt{ { 3 }^{ 2 } } )+ { 2 }^{ 2 } }$$

Evaluate

$$\text{Indeterminate}$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$\sqrt{-2\sqrt{9}+2^{2}}$$

Calculate the square root of 9 and get 3.

$$\sqrt{-2\times 3+2^{2}}$$

Multiply -2 and 3 to get -6.

$$\sqrt{-6+2^{2}}$$

Calculate 2 to the power of 2 and get 4.

$$\sqrt{-6+4}$$

Add -6 and 4 to get -2.

$$\sqrt{-2}$$