Solve sqrt{(2^2*3^2+12^2div4^2)+72div2}

$$\sqrt{ ( { 2 }^{ 2 } \times { 3 }^{ 2 } + { 12 }^{ 2 } \div { 4 }^{ 2 } )+72 \div 2 }$$

Evaluate

$$9$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\sqrt{4\times 3^{2}+\frac{12^{2}}{4^{2}}+\frac{72}{2}}$$

Calculate 3 to the power of 2 and get 9.

$$\sqrt{4\times 9+\frac{12^{2}}{4^{2}}+\frac{72}{2}}$$

Multiply 4 and 9 to get 36.

$$\sqrt{36+\frac{12^{2}}{4^{2}}+\frac{72}{2}}$$

Calculate 12 to the power of 2 and get 144.

$$\sqrt{36+\frac{144}{4^{2}}+\frac{72}{2}}$$

Calculate 4 to the power of 2 and get 16.

$$\sqrt{36+\frac{144}{16}+\frac{72}{2}}$$

Divide 144 by 16 to get 9.

$$\sqrt{36+9+\frac{72}{2}}$$

Add 36 and 9 to get 45.

$$\sqrt{45+\frac{72}{2}}$$

Divide 72 by 2 to get 36.

$$\sqrt{45+36}$$

Add 45 and 36 to get 81.

$$\sqrt{81}$$

Calculate the square root of 81 and get 9.

$$9$$

Factor

$$3^{2}$$