Solve sqrt{2^2+1^2-2*2*1*(-0.25}

$$\sqrt{ { 2 }^{ 2 } + { 1 }^{ 2 } -2 \cdot 2 \cdot 1 \times (-0.25 }$$

Evaluate

$$\sqrt{6}\approx 2.449489743$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\sqrt{4+1^{2}-2\times 2\times 1\left(-0.25\right)}$$

Calculate 1 to the power of 2 and get 1.

$$\sqrt{4+1-2\times 2\times 1\left(-0.25\right)}$$

Add 4 and 1 to get 5.

$$\sqrt{5-2\times 2\times 1\left(-0.25\right)}$$

Multiply 2 and 2 to get 4.

$$\sqrt{5-4\times 1\left(-0.25\right)}$$

Multiply 4 and 1 to get 4.

$$\sqrt{5-4\left(-0.25\right)}$$

Multiply 4 and -0.25 to get -1.

$$\sqrt{5-\left(-1\right)}$$

The opposite of -1 is 1.

$$\sqrt{5+1}$$

Add 5 and 1 to get 6.

$$\sqrt{6}$$