Solve sqrt{left(3-3right)^2+left(-1-4right)^2+left(2-0right)^2}

$$\sqrt{ { \left(3-3 \right) }^{ 2 } + { \left(-1-4 \right) }^{ 2 } + { \left(2-0 \right) }^{ 2 } }$$

Evaluate

$$\sqrt{29}\approx 5.385164807$$

Solution Steps

Subtract 3 from 3 to get 0.

$$\sqrt{0^{2}+\left(-1-4\right)^{2}+\left(2-0\right)^{2}}$$

Calculate 0 to the power of 2 and get 0.

$$\sqrt{0+\left(-1-4\right)^{2}+\left(2-0\right)^{2}}$$

Subtract 4 from -1 to get -5.

$$\sqrt{0+\left(-5\right)^{2}+\left(2-0\right)^{2}}$$

Calculate -5 to the power of 2 and get 25.

$$\sqrt{0+25+\left(2-0\right)^{2}}$$

Add 0 and 25 to get 25.

$$\sqrt{25+\left(2-0\right)^{2}}$$

Subtract 0 from 2 to get 2.

$$\sqrt{25+2^{2}}$$

Calculate 2 to the power of 2 and get 4.

$$\sqrt{25+4}$$

Add 25 and 4 to get 29.

$$\sqrt{29}$$