Solve sqrt{left(3-2right)^2+left(5-4right)^2+left(7-0right)^2}

$$\sqrt{ { \left(3-2 \right) }^{ 2 } + { \left(5-4 \right) }^{ 2 } + { \left(7-0 \right) }^{ 2 } }$$

Evaluate

$$\sqrt{51}\approx 7.141428429$$

Solution Steps

Subtract 2 from 3 to get 1.

$$\sqrt{1^{2}+\left(5-4\right)^{2}+\left(7-0\right)^{2}}$$

Calculate 1 to the power of 2 and get 1.

$$\sqrt{1+\left(5-4\right)^{2}+\left(7-0\right)^{2}}$$

Subtract 4 from 5 to get 1.

$$\sqrt{1+1^{2}+\left(7-0\right)^{2}}$$

Calculate 1 to the power of 2 and get 1.

$$\sqrt{1+1+\left(7-0\right)^{2}}$$

Add 1 and 1 to get 2.

$$\sqrt{2+\left(7-0\right)^{2}}$$

Subtract 0 from 7 to get 7.

$$\sqrt{2+7^{2}}$$

Calculate 7 to the power of 2 and get 49.

$$\sqrt{2+49}$$

Add 2 and 49 to get 51.

$$\sqrt{51}$$