Evaluate
\frac{\sqrt{35}}{10}\approx 0.591607978
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\frac{\sqrt{7}}{\sqrt{20}}
Rewrite the square root of the division \sqrt{\frac{7}{20}} as the division of square roots \frac{\sqrt{7}}{\sqrt{20}}.
\frac{\sqrt{7}}{2\sqrt{5}}
Factor 20=2^{2}\times 5. Rewrite the square root of the product \sqrt{2^{2}\times 5} as the product of square roots \sqrt{2^{2}}\sqrt{5}. Take the square root of 2^{2}.
\frac{\sqrt{7}\sqrt{5}}{2\left(\sqrt{5}\right)^{2}}
Rationalize the denominator of \frac{\sqrt{7}}{2\sqrt{5}} by multiplying numerator and denominator by \sqrt{5}.
\frac{\sqrt{7}\sqrt{5}}{2\times 5}
The square of \sqrt{5} is 5.
\frac{\sqrt{35}}{2\times 5}
To multiply \sqrt{7} and \sqrt{5}, multiply the numbers under the square root.
\frac{\sqrt{35}}{10}
Multiply 2 and 5 to get 10.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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