Solve sqrt{36/49}left(sqrt{121}+sqrt{9}right)

$$\sqrt{ \frac{ 36 }{ 49 } } \left( \sqrt{ 121 } + \sqrt{ 9 } \right)$$

Evaluate

$$12$$

Solution Steps

Rewrite the square root of the division \frac{36}{49} as the division of square roots \frac{\sqrt{36}}{\sqrt{49}}. Take the square root of both numerator and denominator.

$$\frac{6}{7}\left(\sqrt{121}+\sqrt{9}\right)$$

Calculate the square root of 121 and get 11.

$$\frac{6}{7}\left(11+\sqrt{9}\right)$$

Calculate the square root of 9 and get 3.

$$\frac{6}{7}\left(11+3\right)$$

Add 11 and 3 to get 14.

$$\frac{6}{7}\times 14$$

Express \frac{6}{7}\times 14 as a single fraction.

$$\frac{6\times 14}{7}$$

Multiply 6 and 14 to get 84.

$$\frac{84}{7}$$

Divide 84 by 7 to get 12.

$$12$$

Factor

$$2^{2}\times 3$$