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\sqrt{\frac{1+2^{3}+3^{3}+4^{3}+5^{3}}{1^{3}+2^{3}+3^{3}+4^{3}+5^{3}+6^{3}}}
Calculate 1 to the power of 3 and get 1.
\sqrt{\frac{1+8+3^{3}+4^{3}+5^{3}}{1^{3}+2^{3}+3^{3}+4^{3}+5^{3}+6^{3}}}
Calculate 2 to the power of 3 and get 8.
\sqrt{\frac{9+3^{3}+4^{3}+5^{3}}{1^{3}+2^{3}+3^{3}+4^{3}+5^{3}+6^{3}}}
Add 1 and 8 to get 9.
\sqrt{\frac{9+27+4^{3}+5^{3}}{1^{3}+2^{3}+3^{3}+4^{3}+5^{3}+6^{3}}}
Calculate 3 to the power of 3 and get 27.
\sqrt{\frac{36+4^{3}+5^{3}}{1^{3}+2^{3}+3^{3}+4^{3}+5^{3}+6^{3}}}
Add 9 and 27 to get 36.
\sqrt{\frac{36+64+5^{3}}{1^{3}+2^{3}+3^{3}+4^{3}+5^{3}+6^{3}}}
Calculate 4 to the power of 3 and get 64.
\sqrt{\frac{100+5^{3}}{1^{3}+2^{3}+3^{3}+4^{3}+5^{3}+6^{3}}}
Add 36 and 64 to get 100.
\sqrt{\frac{100+125}{1^{3}+2^{3}+3^{3}+4^{3}+5^{3}+6^{3}}}
Calculate 5 to the power of 3 and get 125.
\sqrt{\frac{225}{1^{3}+2^{3}+3^{3}+4^{3}+5^{3}+6^{3}}}
Add 100 and 125 to get 225.
\sqrt{\frac{225}{1+2^{3}+3^{3}+4^{3}+5^{3}+6^{3}}}
Calculate 1 to the power of 3 and get 1.
\sqrt{\frac{225}{1+8+3^{3}+4^{3}+5^{3}+6^{3}}}
Calculate 2 to the power of 3 and get 8.
\sqrt{\frac{225}{9+3^{3}+4^{3}+5^{3}+6^{3}}}
Add 1 and 8 to get 9.
\sqrt{\frac{225}{9+27+4^{3}+5^{3}+6^{3}}}
Calculate 3 to the power of 3 and get 27.
\sqrt{\frac{225}{36+4^{3}+5^{3}+6^{3}}}
Add 9 and 27 to get 36.
\sqrt{\frac{225}{36+64+5^{3}+6^{3}}}
Calculate 4 to the power of 3 and get 64.
\sqrt{\frac{225}{100+5^{3}+6^{3}}}
Add 36 and 64 to get 100.
\sqrt{\frac{225}{100+125+6^{3}}}
Calculate 5 to the power of 3 and get 125.
\sqrt{\frac{225}{225+6^{3}}}
Add 100 and 125 to get 225.
\sqrt{\frac{225}{225+216}}
Calculate 6 to the power of 3 and get 216.
\sqrt{\frac{225}{441}}
Add 225 and 216 to get 441.
\sqrt{\frac{25}{49}}
Reduce the fraction \frac{225}{441} to lowest terms by extracting and canceling out 9.
\frac{5}{7}
Rewrite the square root of the division \frac{25}{49} as the division of square roots \frac{\sqrt{25}}{\sqrt{49}}. Take the square root of both numerator and denominator.