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\sqrt[3]{\frac{1}{25}}+\sqrt[3]{\frac{2^{3}}{5}}
Reduce the fraction \frac{5}{125} to lowest terms by extracting and canceling out 5.
\sqrt[3]{\frac{1}{25}}+\sqrt[3]{\frac{8}{5}}
Calculate 2 to the power of 3 and get 8.