Solve sqrt[9]{2^2*14^2*(7*4-3)+6*14-1}=

$$\sqrt[ 9 ] { 2 ^ { 2 } \cdot 14 ^ { 2 } \cdot ( 7 \cdot 4 - 3 ) + 6 \cdot 14 - 1 } =$$

Evaluate

$$3$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\sqrt[9]{4\times 14^{2}\left(7\times 4-3\right)+6\times 14-1}$$

Calculate 14 to the power of 2 and get 196.

$$\sqrt[9]{4\times 196\left(7\times 4-3\right)+6\times 14-1}$$

Multiply 4 and 196 to get 784.

$$\sqrt[9]{784\left(7\times 4-3\right)+6\times 14-1}$$

Multiply 7 and 4 to get 28.

$$\sqrt[9]{784\left(28-3\right)+6\times 14-1}$$

Subtract 3 from 28 to get 25.

$$\sqrt[9]{784\times 25+6\times 14-1}$$

Multiply 784 and 25 to get 19600.

$$\sqrt[9]{19600+6\times 14-1}$$

Multiply 6 and 14 to get 84.

$$\sqrt[9]{19600+84-1}$$

Add 19600 and 84 to get 19684.

$$\sqrt[9]{19684-1}$$

Subtract 1 from 19684 to get 19683.

$$\sqrt[9]{19683}$$

Calculate \sqrt[9]{19683} and get 3.

$$3$$

Factor

$$3$$