Solve sqrt[5]{-32}*(4^7/4^5)

$$\sqrt[ 5 ] { - 32 } \times ( \frac { 4 ^ { 7 } } { 4 ^ { 5 } } )$$

Evaluate

$$-32$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 5 from 7 to get 2.

$$\sqrt[5]{-32}\times 4^{2}$$

Calculate \sqrt[5]{-32} and get -2.

$$-2\times 4^{2}$$

Calculate 4 to the power of 2 and get 16.

$$-2\times 16$$

Multiply -2 and 16 to get -32.

$$-32$$

Factor

$$-32$$