Solve sqrt[4]{1/81}+(2/3)^-1-0,002*10^3

$$\sqrt[ 4 ] { \frac { 1 } { 81 } } + ( \frac { 2 } { 3 } ) ^ { - 1 } - 0,002 \times 10 ^ { 3 }$$

Evaluate

$$-\frac{1}{6}\approx -0,166666667$$

Solution Steps

Calculate \sqrt[4]{\frac{1}{81}} and get \frac{1}{3}.

$$\frac{1}{3}+\left(\frac{2}{3}\right)^{-1}-0,002\times 10^{3}$$

Calculate \frac{2}{3} to the power of -1 and get \frac{3}{2}.

$$\frac{1}{3}+\frac{3}{2}-0,002\times 10^{3}$$

Add \frac{1}{3} and \frac{3}{2} to get \frac{11}{6}.

$$\frac{11}{6}-0,002\times 10^{3}$$

Calculate 10 to the power of 3 and get 1000.

$$\frac{11}{6}-0,002\times 1000$$

Multiply 0,002 and 1000 to get 2.

$$\frac{11}{6}-2$$

Subtract 2 from \frac{11}{6} to get -\frac{1}{6}.

$$-\frac{1}{6}$$

Factor

$$-\frac{1}{6} = -0.16666666666666666$$