Evaluate
7\sqrt{3}\approx 12.124355653
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\sqrt[4]{9}=\sqrt[4]{3^{2}}=3^{\frac{2}{4}}=3^{\frac{1}{2}}=\sqrt{3}
Rewrite \sqrt[4]{9} as \sqrt[4]{3^{2}}. Convert from radical to exponential form and cancel out 2 in the exponent. Convert back to radical form.
\sqrt{3}-3\sqrt[3]{3}+\sqrt{108}+\sqrt[3]{81}
Insert the obtained value back in the expression.
\sqrt{3}-3\sqrt[3]{3}+6\sqrt{3}+\sqrt[3]{81}
Factor 108=6^{2}\times 3. Rewrite the square root of the product \sqrt{6^{2}\times 3} as the product of square roots \sqrt{6^{2}}\sqrt{3}. Take the square root of 6^{2}.
7\sqrt{3}-3\sqrt[3]{3}+\sqrt[3]{81}
Combine \sqrt{3} and 6\sqrt{3} to get 7\sqrt{3}.
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