Solve sqrt[3]{8}(4+2*3)^3-9(3-2)+4

$$\sqrt[ 3 ] { 8 } ( 4 + 2 \times 3 ) ^ { 3 } - 9 ( 3 - 2 ) + 4$$

Evaluate

$$1995$$

Solution Steps

Calculate \sqrt[3]{8} and get 2.

$$2\left(4+2\times 3\right)^{3}-9\left(3-2\right)+4$$

Multiply 2 and 3 to get 6.

$$2\left(4+6\right)^{3}-9\left(3-2\right)+4$$

Add 4 and 6 to get 10.

$$2\times 10^{3}-9\left(3-2\right)+4$$

Calculate 10 to the power of 3 and get 1000.

$$2\times 1000-9\left(3-2\right)+4$$

Multiply 2 and 1000 to get 2000.

$$2000-9\left(3-2\right)+4$$

Subtract 2 from 3 to get 1.

$$2000-9\times 1+4$$

Multiply 9 and 1 to get 9.

$$2000-9+4$$

Subtract 9 from 2000 to get 1991.

$$1991+4$$

Add 1991 and 4 to get 1995.

$$1995$$

Factor

$$3\times 5\times 7\times 19$$