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2+3\sqrt[3]{16}-4+\sqrt{54}
Calculate \sqrt[3]{8} and get 2.
-2+3\sqrt[3]{16}+\sqrt{54}
Subtract 4 from 2 to get -2.
-2+3\sqrt[3]{16}+3\sqrt{6}
Factor 54=3^{2}\times 6. Rewrite the square root of the product \sqrt{3^{2}\times 6} as the product of square roots \sqrt{3^{2}}\sqrt{6}. Take the square root of 3^{2}.