Solve sqrt[3]{32}=sqrt[3]{2^3*4}=

$$\sqrt[ 3 ] { 32 } = \sqrt[ 3 ] { 2 ^ { 3 } \times 4 } =$$

Verify

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$\sqrt[3]{32}=\sqrt[3]{8\times 4}$$

Multiply 8 and 4 to get 32.

$$\sqrt[3]{32}=\sqrt[3]{32}$$

Subtract \sqrt[3]{32} from both sides.

$$\sqrt[3]{32}-\sqrt[3]{32}=0$$

Combine \sqrt[3]{32} and -\sqrt[3]{32} to get 0.

$$0=0$$

Compare 0 and 0.

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