Evaluate
3\sqrt[3]{2}+7990\approx 7993.77976315
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\sqrt[3]{54}+20^{3}-\left(\frac{1}{10}\right)^{-1}
Add 24 and 30 to get 54.
\sqrt[3]{54}+8000-\left(\frac{1}{10}\right)^{-1}
Calculate 20 to the power of 3 and get 8000.
\sqrt[3]{54}+8000-10
Calculate \frac{1}{10} to the power of -1 and get 10.
\sqrt[3]{54}+7990
Subtract 10 from 8000 to get 7990.
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