Solve sqrt[3]{21952}=sqrt[3]{(2^6*7^3)}=

$$\sqrt[ 3 ] { 21952 } = \sqrt[ 3 ] { ( 2 ^ { 6 } \cdot 7 ^ { 3 } ) } =$$

Verify

Solution Steps

Calculate \sqrt[3]{21952} and get 28.

$$28=\sqrt[3]{2^{6}\times 7^{3}}$$

Calculate 2 to the power of 6 and get 64.

$$28=\sqrt[3]{64\times 7^{3}}$$

Calculate 7 to the power of 3 and get 343.

$$28=\sqrt[3]{64\times 343}$$

Multiply 64 and 343 to get 21952.

$$28=\sqrt[3]{21952}$$

Calculate \sqrt[3]{21952} and get 28.

$$28=28$$

Compare 28 and 28.

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