Solve sqrt[3]{1-9}-(-2)^2*3div(-6)

$$\sqrt[ 3 ] { 1 - 9 } - ( - 2 ) ^ { 2 } \cdot 3 \div ( - 6 )$$

Evaluate

$$0$$

Solution Steps

Subtract 9 from 1 to get -8.

$$\sqrt[3]{-8}-\frac{\left(-2\right)^{2}\times 3}{-6}$$

Calculate \sqrt[3]{-8} and get -2.

$$-2-\frac{\left(-2\right)^{2}\times 3}{-6}$$

Calculate -2 to the power of 2 and get 4.

$$-2-\frac{4\times 3}{-6}$$

Multiply 4 and 3 to get 12.

$$-2-\frac{12}{-6}$$

Divide 12 by -6 to get -2.

$$-2-\left(-2\right)$$

The opposite of -2 is 2.

$$-2+2$$

Add -2 and 2 to get 0.

$$0$$

Factor

$$0$$