Solve sqrt[3]{1+30000+2*10^8+10^8+10^12}

$$\sqrt[ 3 ] { 1 + 30000 + 2 \cdot 10 ^ { 8 } + 10 ^ { 8 } + 10 ^ { 12 } }$$

Evaluate

$$10001$$

Solution Steps

Add 1 and 30000 to get 30001.

$$\sqrt[3]{30001+2\times 10^{8}+10^{8}+10^{12}}$$

Calculate 10 to the power of 8 and get 100000000.

$$\sqrt[3]{30001+2\times 100000000+10^{8}+10^{12}}$$

Multiply 2 and 100000000 to get 200000000.

$$\sqrt[3]{30001+200000000+10^{8}+10^{12}}$$

Add 30001 and 200000000 to get 200030001.

$$\sqrt[3]{200030001+10^{8}+10^{12}}$$

Calculate 10 to the power of 8 and get 100000000.

$$\sqrt[3]{200030001+100000000+10^{12}}$$

Add 200030001 and 100000000 to get 300030001.

$$\sqrt[3]{300030001+10^{12}}$$

Calculate 10 to the power of 12 and get 1000000000000.

$$\sqrt[3]{300030001+1000000000000}$$

Add 300030001 and 1000000000000 to get 1000300030001.

$$\sqrt[3]{1000300030001}$$

Calculate \sqrt[3]{1000300030001} and get 10001.

$$10001$$

Factor

$$73\times 137$$