Solve sqrt[3]{-8}*(-5)^2+4div2+3*(-3)+sqrt{64}div(-4)=

$$\sqrt[ 3 ] { - 8 } \times ( - 5 ) ^ { 2 } + 4 \div 2 + 3 \cdot ( - 3 ) + \sqrt { 64 } \div ( - 4 ) =$$

Evaluate

$$-59$$

Solution Steps

Calculate \sqrt[3]{-8} and get -2.

$$-2\left(-5\right)^{2}+\frac{4}{2}+3\left(-3\right)+\frac{\sqrt{64}}{-4}$$

Calculate -5 to the power of 2 and get 25.

$$-2\times 25+\frac{4}{2}+3\left(-3\right)+\frac{\sqrt{64}}{-4}$$

Multiply -2 and 25 to get -50.

$$-50+\frac{4}{2}+3\left(-3\right)+\frac{\sqrt{64}}{-4}$$

Divide 4 by 2 to get 2.

$$-50+2+3\left(-3\right)+\frac{\sqrt{64}}{-4}$$

Add -50 and 2 to get -48.

$$-48+3\left(-3\right)+\frac{\sqrt{64}}{-4}$$

Multiply 3 and -3 to get -9.

$$-48-9+\frac{\sqrt{64}}{-4}$$

Subtract 9 from -48 to get -57.

$$-57+\frac{\sqrt{64}}{-4}$$

Calculate the square root of 64 and get 8.

$$-57+\frac{8}{-4}$$

Divide 8 by -4 to get -2.

$$-57-2$$

Subtract 2 from -57 to get -59.

$$-59$$

Factor

$$-59$$