Solve sqrt[3]{-8}*(-5)+4div2+3*(-3)+sqrt{64}div(-4)

$$\sqrt[ 3 ] { - 8 } \times ( - 5 ) + 4 \div 2 + 3 \cdot ( - 3 ) + \sqrt { 64 } \div ( - 4 )$$

Evaluate

$$1$$

Solution Steps

Calculate \sqrt[3]{-8} and get -2.

$$-2\left(-5\right)+\frac{4}{2}+3\left(-3\right)+\frac{\sqrt{64}}{-4}$$

Multiply -2 and -5 to get 10.

$$10+\frac{4}{2}+3\left(-3\right)+\frac{\sqrt{64}}{-4}$$

Divide 4 by 2 to get 2.

$$10+2+3\left(-3\right)+\frac{\sqrt{64}}{-4}$$

Add 10 and 2 to get 12.

$$12+3\left(-3\right)+\frac{\sqrt{64}}{-4}$$

Multiply 3 and -3 to get -9.

$$12-9+\frac{\sqrt{64}}{-4}$$

Subtract 9 from 12 to get 3.

$$3+\frac{\sqrt{64}}{-4}$$

Calculate the square root of 64 and get 8.

$$3+\frac{8}{-4}$$

Divide 8 by -4 to get -2.

$$3-2$$

Subtract 2 from 3 to get 1.

$$1$$

Factor

$$1$$