Solve sqrt[3]{-15+7}-(-2)(1-3^2+(-1)^3)+(-1)^2

$$\sqrt[ 3 ] { - 15 + 7 } - ( - 2 ) ( 1 - 3 ^ { 2 } + ( - 1 ) ^ { 3 } ) + ( - 1 ) ^ { 2 }$$

Evaluate

$$-19$$

Solution Steps

Add -15 and 7 to get -8.

$$\sqrt[3]{-8}-\left(-2\left(1-3^{2}+\left(-1\right)^{3}\right)\right)+\left(-1\right)^{2}$$

Calculate \sqrt[3]{-8} and get -2.

$$-2-\left(-2\left(1-3^{2}+\left(-1\right)^{3}\right)\right)+\left(-1\right)^{2}$$

Calculate 3 to the power of 2 and get 9.

$$-2-\left(-2\left(1-9+\left(-1\right)^{3}\right)\right)+\left(-1\right)^{2}$$

Subtract 9 from 1 to get -8.

$$-2-\left(-2\left(-8+\left(-1\right)^{3}\right)\right)+\left(-1\right)^{2}$$

Calculate -1 to the power of 3 and get -1.

$$-2-\left(-2\left(-8-1\right)\right)+\left(-1\right)^{2}$$

Subtract 1 from -8 to get -9.

$$-2-\left(-2\left(-9\right)\right)+\left(-1\right)^{2}$$

Multiply -2 and -9 to get 18.

$$-2-18+\left(-1\right)^{2}$$

Subtract 18 from -2 to get -20.

$$-20+\left(-1\right)^{2}$$

Calculate -1 to the power of 2 and get 1.

$$-20+1$$

Add -20 and 1 to get -19.

$$-19$$

Factor

$$-19$$