Solve sqrt[3]{(-6)^3}-sqrt[3]{-27}-(-2)^2

$$\sqrt[ 3 ] { ( - 6 ) ^ { 3 } } - \sqrt[ 3 ] { - 27 } - ( - 2 ) ^ { 2 }$$

Evaluate

$$-7$$

Solution Steps

Calculate -6 to the power of 3 and get -216.

$$\sqrt[3]{-216}-\sqrt[3]{-27}-\left(-2\right)^{2}$$

Calculate \sqrt[3]{-216} and get -6.

$$-6-\sqrt[3]{-27}-\left(-2\right)^{2}$$

Calculate \sqrt[3]{-27} and get -3.

$$-6-\left(-3\right)-\left(-2\right)^{2}$$

The opposite of -3 is 3.

$$-6+3-\left(-2\right)^{2}$$

Add -6 and 3 to get -3.

$$-3-\left(-2\right)^{2}$$

Calculate -2 to the power of 2 and get 4.

$$-3-4$$

Subtract 4 from -3 to get -7.

$$-7$$

Factor

$$-7$$