Solve sqrt[3]{646/125-11}-sqrt{01^-2}+sqrt[3]{8^2}

$$\sqrt[ 3 ] { \frac { 646 } { 125 } - 11 } - \sqrt { 01 ^ { - 2 } } + \sqrt[ 3 ] { 8 ^ { 2 } }$$

Evaluate

$$\frac{11}{5}=2.2$$

Solution Steps

Subtract 11 from \frac{646}{125} to get -\frac{729}{125}.

$$\sqrt[3]{-\frac{729}{125}}-\sqrt{0\times 1^{-2}}+\sqrt[3]{8^{2}}$$

Calculate \sqrt[3]{-\frac{729}{125}} and get -\frac{9}{5}.

$$-\frac{9}{5}-\sqrt{0\times 1^{-2}}+\sqrt[3]{8^{2}}$$

Calculate 1 to the power of -2 and get 1.

$$-\frac{9}{5}-\sqrt{0\times 1}+\sqrt[3]{8^{2}}$$

Multiply 0 and 1 to get 0.

$$-\frac{9}{5}-\sqrt{0}+\sqrt[3]{8^{2}}$$

Calculate the square root of 0 and get 0.

$$-\frac{9}{5}-0+\sqrt[3]{8^{2}}$$

Multiply -1 and 0 to get 0.

$$-\frac{9}{5}+0+\sqrt[3]{8^{2}}$$

Add -\frac{9}{5} and 0 to get -\frac{9}{5}.

$$-\frac{9}{5}+\sqrt[3]{8^{2}}$$

Calculate 8 to the power of 2 and get 64.

$$-\frac{9}{5}+\sqrt[3]{64}$$

Calculate \sqrt[3]{64} and get 4.

$$-\frac{9}{5}+4$$

Add -\frac{9}{5} and 4 to get \frac{11}{5}.

$$\frac{11}{5}$$

Factor

$$\frac{11}{5} = 2\frac{1}{5} = 2.2$$