Solve sqrt[3]{0*04}sqrt[6]{625}

$$\sqrt[ 3 ]{ 0 \cdot 04 } \sqrt[ 6 ]{ 625 }$$

Evaluate

$$0$$

Solution Steps

Multiply 0 and 0 to get 0.

$$\sqrt[3]{0\times 4}\sqrt[6]{625}$$

Multiply 0 and 4 to get 0.

$$\sqrt[3]{0}\sqrt[6]{625}$$

Calculate \sqrt[3]{0} and get 0.

$$0\sqrt[6]{625}$$

Rewrite \sqrt[6]{625} as \sqrt[6]{25^{2}}. Convert from radical to exponential form and cancel out 2 in the exponent. Convert back to radical form.

$$\sqrt[6]{625}=\sqrt[6]{25^{2}}=25^{\frac{2}{6}}=25^{\frac{1}{3}}=\sqrt[3]{25}$$

Insert the obtained value back in the expression.

$$0\sqrt[3]{25}$$

Anything times zero gives zero.

$$0$$

Factor

$$0$$