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\sqrt[3]{-\frac{1}{64}}+\sqrt[3]{7^{3}}
Calculate 8 to the power of -2 and get \frac{1}{64}.
-\frac{1}{4}+\sqrt[3]{7^{3}}
Calculate \sqrt[3]{-\frac{1}{64}} and get -\frac{1}{4}.
-\frac{1}{4}+\sqrt[3]{343}
Calculate 7 to the power of 3 and get 343.
-\frac{1}{4}+7
Calculate \sqrt[3]{343} and get 7.
\frac{27}{4}
Add -\frac{1}{4} and 7 to get \frac{27}{4}.