Solve sqrt[1]{2299968}=sqrt[3]{(2^6*3^3*11^3)}

$$\sqrt[ 1 ] { 2299968 } = \sqrt[ 3 ] { ( 2 ^ { 6 } \cdot 3 ^ { 3 } \cdot 11 ^ { 3 } ) }$$

Verify

Solution Steps

Calculate \sqrt[1]{2299968} and get 2299968.

$$2299968=\sqrt[3]{2^{6}\times 3^{3}\times 11^{3}}$$

Calculate 2 to the power of 6 and get 64.

$$2299968=\sqrt[3]{64\times 3^{3}\times 11^{3}}$$

Calculate 3 to the power of 3 and get 27.

$$2299968=\sqrt[3]{64\times 27\times 11^{3}}$$

Multiply 64 and 27 to get 1728.

$$2299968=\sqrt[3]{1728\times 11^{3}}$$

Calculate 11 to the power of 3 and get 1331.

$$2299968=\sqrt[3]{1728\times 1331}$$

Multiply 1728 and 1331 to get 2299968.

$$2299968=\sqrt[3]{2299968}$$

Calculate \sqrt[3]{2299968} and get 132.

$$2299968=132$$

Compare 2299968 and 132.

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