Solve for y
y=12
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\sqrt{y-8}+5-5=7-5
Subtract 5 from both sides of the equation.
\sqrt{y-8}=7-5
Subtracting 5 from itself leaves 0.
\sqrt{y-8}=2
Subtract 5 from 7.
y-8=4
Square both sides of the equation.
y-8-\left(-8\right)=4-\left(-8\right)
Add 8 to both sides of the equation.
y=4-\left(-8\right)
Subtracting -8 from itself leaves 0.
y=12
Subtract -8 from 4.
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{ x } ^ { 2 } - 4 x - 5 = 0
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Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
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\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
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