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\left(\sqrt{x-8}\right)^{2}=\left(\sqrt{3x-34}\right)^{2}
Square both sides of the equation.
x-8=\left(\sqrt{3x-34}\right)^{2}
Calculate \sqrt{x-8} to the power of 2 and get x-8.
x-8=3x-34
Calculate \sqrt{3x-34} to the power of 2 and get 3x-34.
x-8-3x=-34
Subtract 3x from both sides.
-2x-8=-34
Combine x and -3x to get -2x.
-2x=-34+8
Add 8 to both sides.
-2x=-26
Add -34 and 8 to get -26.
x=\frac{-26}{-2}
Divide both sides by -2.
x=13
Divide -26 by -2 to get 13.
\sqrt{13-8}=\sqrt{3\times 13-34}
Substitute 13 for x in the equation \sqrt{x-8}=\sqrt{3x-34}.
5^{\frac{1}{2}}=5^{\frac{1}{2}}
Simplify. The value x=13 satisfies the equation.
x=13
Equation \sqrt{x-8}=\sqrt{3x-34} has a unique solution.