Solve for x
x=11
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\sqrt{x-2}=x-8
Subtract 8 from both sides of the equation.
\left(\sqrt{x-2}\right)^{2}=\left(x-8\right)^{2}
Square both sides of the equation.
x-2=\left(x-8\right)^{2}
Calculate \sqrt{x-2} to the power of 2 and get x-2.
x-2=x^{2}-16x+64
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-8\right)^{2}.
x-2-x^{2}=-16x+64
Subtract x^{2} from both sides.
x-2-x^{2}+16x=64
Add 16x to both sides.
17x-2-x^{2}=64
Combine x and 16x to get 17x.
17x-2-x^{2}-64=0
Subtract 64 from both sides.
17x-66-x^{2}=0
Subtract 64 from -2 to get -66.
-x^{2}+17x-66=0
Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=17 ab=-\left(-66\right)=66
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as -x^{2}+ax+bx-66. To find a and b, set up a system to be solved.
1,66 2,33 3,22 6,11
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 66.
1+66=67 2+33=35 3+22=25 6+11=17
Calculate the sum for each pair.
a=11 b=6
The solution is the pair that gives sum 17.
\left(-x^{2}+11x\right)+\left(6x-66\right)
Rewrite -x^{2}+17x-66 as \left(-x^{2}+11x\right)+\left(6x-66\right).
-x\left(x-11\right)+6\left(x-11\right)
Factor out -x in the first and 6 in the second group.
\left(x-11\right)\left(-x+6\right)
Factor out common term x-11 by using distributive property.
x=11 x=6
To find equation solutions, solve x-11=0 and -x+6=0.
\sqrt{11-2}+8=11
Substitute 11 for x in the equation \sqrt{x-2}+8=x.
11=11
Simplify. The value x=11 satisfies the equation.
\sqrt{6-2}+8=6
Substitute 6 for x in the equation \sqrt{x-2}+8=x.
10=6
Simplify. The value x=6 does not satisfy the equation.
x=11
Equation \sqrt{x-2}=x-8 has a unique solution.
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Simultaneous equation
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Limits
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