Solve sqrt{x+4}=2Y

$$\sqrt { x + 4 } = 2 Y$$

Solve for x

$$x=4\left(Y^{2}-1\right)$$

$$Y\geq 0$$

Steps for Solving Radical Equations

Square both sides of the equation.

$$x+4=4Y^{2}$$

Subtract 4 from both sides of the equation.

$$x+4-4=4Y^{2}-4$$

Subtracting 4 from itself leaves 0.

$$x=4Y^{2}-4$$

Solve for Y (complex solution)

$$Y=\frac{\sqrt{x+4}}{2}$$

Solve for x (complex solution)

$$x=4\left(Y^{2}-1\right)$$

$$arg(Y)<\pi \text{ or }Y=0$$

Solve for Y

$$Y=\frac{\sqrt{x+4}}{2}$$

$$x\geq -4$$