Solve sqrt{x+3}+(y-5)^2=0

$$\sqrt { x + 3 } + ( y - 5 ) ^ { 2 } = 0$$

Solve for x

$$x=-3$$

$$y=5$$

Steps for Solving Radical Equations

Subtract \left(y-5\right)^{2} from both sides of the equation.

$$\sqrt{x+3}+\left(y-5\right)^{2}-\left(y-5\right)^{2}=-\left(y-5\right)^{2}$$

Subtracting \left(y-5\right)^{2} from itself leaves 0.

$$\sqrt{x+3}=-\left(y-5\right)^{2}$$

Square both sides of the equation.

$$x+3=\left(y-5\right)^{4}$$

Subtract 3 from both sides of the equation.

$$x+3-3=\left(y-5\right)^{4}-3$$

Subtracting 3 from itself leaves 0.

$$x=\left(y-5\right)^{4}-3$$

Solve for y

$$y=5$$

$$x=-3$$