Solve sqrt{98}-sqrt{50}=

$$\sqrt { 98 } - \sqrt { 50 } =$$

Evaluate

$$2\sqrt{2}\approx 2.828427125$$

Solution Steps

Factor 98=7^{2}\times 2. Rewrite the square root of the product \sqrt{7^{2}\times 2} as the product of square roots \sqrt{7^{2}}\sqrt{2}. Take the square root of 7^{2}.

$$7\sqrt{2}-\sqrt{50}$$

Factor 50=5^{2}\times 2. Rewrite the square root of the product \sqrt{5^{2}\times 2} as the product of square roots \sqrt{5^{2}}\sqrt{2}. Take the square root of 5^{2}.

$$7\sqrt{2}-5\sqrt{2}$$

Combine 7\sqrt{2} and -5\sqrt{2} to get 2\sqrt{2}.

$$2\sqrt{2}$$