Solve sqrt{98}+sqrt{50}

$$\sqrt { 98 } + \sqrt { 50 }$$

Evaluate

$$12\sqrt{2}\approx 16.970562748$$

Solution Steps

Factor 98=7^{2}\times 2. Rewrite the square root of the product \sqrt{7^{2}\times 2} as the product of square roots \sqrt{7^{2}}\sqrt{2}. Take the square root of 7^{2}.

$$7\sqrt{2}+\sqrt{50}$$

Factor 50=5^{2}\times 2. Rewrite the square root of the product \sqrt{5^{2}\times 2} as the product of square roots \sqrt{5^{2}}\sqrt{2}. Take the square root of 5^{2}.

$$7\sqrt{2}+5\sqrt{2}$$

Combine 7\sqrt{2} and 5\sqrt{2} to get 12\sqrt{2}.

$$12\sqrt{2}$$