Solve sqrt{9}-sqrt{(-6)^2}-sqrt[3]{-27}-(-1)^2017

$$\sqrt { 9 } - \sqrt { ( - 6 ) ^ { 2 } } - \sqrt[ 3 ] { - 27 } - ( - 1 ) ^ { 2017 }$$

Evaluate

$$1$$

Solution Steps

Calculate the square root of 9 and get 3.

$$3-\sqrt{\left(-6\right)^{2}}-\sqrt[3]{-27}-\left(-1\right)^{2017}$$

Calculate -6 to the power of 2 and get 36.

$$3-\sqrt{36}-\sqrt[3]{-27}-\left(-1\right)^{2017}$$

Calculate the square root of 36 and get 6.

$$3-6-\sqrt[3]{-27}-\left(-1\right)^{2017}$$

Subtract 6 from 3 to get -3.

$$-3-\sqrt[3]{-27}-\left(-1\right)^{2017}$$

Calculate \sqrt[3]{-27} and get -3.

$$-3-\left(-3\right)-\left(-1\right)^{2017}$$

The opposite of -3 is 3.

$$-3+3-\left(-1\right)^{2017}$$

Add -3 and 3 to get 0.

$$0-\left(-1\right)^{2017}$$

Calculate -1 to the power of 2017 and get -1.

$$0-\left(-1\right)$$

The opposite of -1 is 1.

$$0+1$$

Add 0 and 1 to get 1.

$$1$$

Factor

$$1$$