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3\left(\sqrt{3}+\sqrt{8}\right)
Calculate the square root of 9 and get 3.
3\left(\sqrt{3}+2\sqrt{2}\right)
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
3\sqrt{3}+6\sqrt{2}
Use the distributive property to multiply 3 by \sqrt{3}+2\sqrt{2}.