Solve sqrt{9}*3^5-4^2+(6^3+2^4)

$$\sqrt { 9 } \times 3 ^ { 5 } - 4 ^ { 2 } + ( 6 ^ { 3 } + 2 ^ { 4 } )$$

Evaluate

$$945$$

Solution Steps

Calculate the square root of 9 and get 3.

$$3\times 3^{5}-4^{2}+6^{3}+2^{4}$$

Calculate 3 to the power of 5 and get 243.

$$3\times 243-4^{2}+6^{3}+2^{4}$$

Multiply 3 and 243 to get 729.

$$729-4^{2}+6^{3}+2^{4}$$

Calculate 4 to the power of 2 and get 16.

$$729-16+6^{3}+2^{4}$$

Subtract 16 from 729 to get 713.

$$713+6^{3}+2^{4}$$

Calculate 6 to the power of 3 and get 216.

$$713+216+2^{4}$$

Add 713 and 216 to get 929.

$$929+2^{4}$$

Calculate 2 to the power of 4 and get 16.

$$929+16$$

Add 929 and 16 to get 945.

$$945$$

Factor

$$3^{3}\times 5\times 7$$