Solve sqrt{9}=sqrt3^2=3

$$\sqrt { 9 } = \sqrt { 3 } ^ { 2 } = 3$$

Verify

Solution Steps

Calculate the square root of 9 and get 3.

$$3=\left(\sqrt{3}\right)^{2}\text{ and }\left(\sqrt{3}\right)^{2}=3$$

The square of \sqrt{3} is 3.

$$3=3\text{ and }\left(\sqrt{3}\right)^{2}=3$$

Compare 3 and 3.

$$\text{true}\text{ and }\left(\sqrt{3}\right)^{2}=3$$

The square of \sqrt{3} is 3.

$$\text{true}\text{ and }3=3$$

Compare 3 and 3.

$$\text{true}\text{ and }\text{true}$$

The conjunction of \text{true} and \text{true} is \text{true}.

$$\text{true}$$