Solve sqrt{9}+3div2-25=

$$\sqrt { 9 } + 3 \div 2 - 25 =$$

Evaluate

$$-\frac{41}{2}=-20.5$$

Solution Steps

Calculate the square root of 9 and get 3.

$$3+\frac{3}{2}-25$$

Convert 3 to fraction \frac{6}{2}.

$$\frac{6}{2}+\frac{3}{2}-25$$

Since \frac{6}{2} and \frac{3}{2} have the same denominator, add them by adding their numerators.

$$\frac{6+3}{2}-25$$

Add 6 and 3 to get 9.

$$\frac{9}{2}-25$$

Convert 25 to fraction \frac{50}{2}.

$$\frac{9}{2}-\frac{50}{2}$$

Since \frac{9}{2} and \frac{50}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-50}{2}$$

Subtract 50 from 9 to get -41.

$$-\frac{41}{2}$$

Factor

$$-\frac{41}{2} = -20\frac{1}{2} = -20.5$$