Solve sqrt{81}:3-25^2:5+4.2*16:44=

$$\sqrt { 81 } : 3 - 25 ^ { 2 } : 5 + 4.2 \cdot 16 : 44 =$$

Evaluate

$$-\frac{6626}{55}\approx -120.472727273$$

Solution Steps

Calculate the square root of 81 and get 9.

$$\frac{9}{3}-\frac{25^{2}}{5}+\frac{4.2\times 16}{44}$$

Divide 9 by 3 to get 3.

$$3-\frac{25^{2}}{5}+\frac{4.2\times 16}{44}$$

Calculate 25 to the power of 2 and get 625.

$$3-\frac{625}{5}+\frac{4.2\times 16}{44}$$

Divide 625 by 5 to get 125.

$$3-125+\frac{4.2\times 16}{44}$$

Subtract 125 from 3 to get -122.

$$-122+\frac{4.2\times 16}{44}$$

Multiply 4.2 and 16 to get 67.2.

$$-122+\frac{67.2}{44}$$

Expand \frac{67.2}{44} by multiplying both numerator and the denominator by 10.

$$-122+\frac{672}{440}$$

Reduce the fraction \frac{672}{440} to lowest terms by extracting and canceling out 8.

$$-122+\frac{84}{55}$$

Convert -122 to fraction -\frac{6710}{55}.

$$-\frac{6710}{55}+\frac{84}{55}$$

Since -\frac{6710}{55} and \frac{84}{55} have the same denominator, add them by adding their numerators.

$$\frac{-6710+84}{55}$$

Add -6710 and 84 to get -6626.

$$-\frac{6626}{55}$$

Factor

$$-\frac{6626}{55} = -120\frac{26}{55} = -120.47272727272727$$