Solve sqrt{8x+1}+12=15

$$\sqrt { 8 x + 1 } + 12 = 15$$

Solve for x

$$x=1$$

Steps for Solving Radical Equations

Subtract 12 from both sides of the equation.

$$\sqrt{8x+1}+12-12=15-12$$

Subtracting 12 from itself leaves 0.

$$\sqrt{8x+1}=15-12$$

Subtract 12 from 15.

$$\sqrt{8x+1}=3$$

Square both sides of the equation.

$$8x+1=9$$

Subtract 1 from both sides of the equation.

$$8x+1-1=9-1$$

Subtracting 1 from itself leaves 0.

$$8x=9-1$$

Subtract 1 from 9.

$$8x=8$$

Divide both sides by 8.

$$\frac{8x}{8}=\frac{8}{8}$$

Dividing by 8 undoes the multiplication by 8.

$$x=\frac{8}{8}$$

Divide 8 by 8.

$$x=1$$